2t^2=2.0t+5.6

Solution for 2t^2=2.0t+5.6 equation:

2t^2=2.0t+5.6

We move all terms to the left:

2t^2-(2.0t+5.6)=0

We get rid of parentheses

2t^2-2.0t-5.6=0

We add all the numbers together, and all the variables

2t^2-2t-5.6=0

a = 2; b = -2; c = -5.6;
Δ = b2-4ac
Δ = -22-4·2·(-5.6)
Δ = 48.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{48.8}}{2*2}=\frac{2-\sqrt{48.8}}{4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{48.8}}{2*2}=\frac{2+\sqrt{48.8}}{4}
$